# Line slope calculator 3x+5y=33

**Straight line given by points A[1; 6] and B[6; 3]**

## Calculation:

**Slope-intercept form of line:**y = -0.6x+6.6

**Canonical form of the line equation:**3x+5y-33 = 0

**Parametric form of the line equation:**

x = 5t+1

y = -3t+6 ; t ∈ R

**Slope:**m = -0.6

**Slope angle of line: φ =**-30°57'50″ = -0.5404 rad

**X intercept:**x

_{0}= 11

**Y intercept:**y

_{0}= q = 6.6

**Distance line from the origin:**d

_{0}= 5.6595

**The length of the segment AB: |AB| =**5.831

**Vector: AB =**(5; -3)

**Normal vector: n =**(3; 5)

**Midpoint of the segment AB: M =**[3.5; 4.5]

**Perpendicular Bisector equation:**5x-3y-4 = 0

**Vector OA = (1; 6) ; |OA| = 6.0828**

**Vector OB = (6; 3) ; |OB| = 6.7082**

**Scalar product OA .OB = 24**

**Angle ∠ AOB = 53°58'21″ = 0.942 rad**